An organization has an account management policy that defines parameters around each type of account. that policy specifies different security attributes, such as longevity, usage auditing, password complexity, and identity proofing. the goal of the account management policy is to ensure the highest level of security while providing the greatest availability without compromising data integrity for users. which of the following account types should the policy specify for service technicians from corporate partners?

- guest account

- user account

- shared account

- privileged user account

- default account

- service account

You have a linux system that has a 1000gb hard disk drive, which has a 90gb partition containing an ext4 filesystem mounted to the / directory and a 4gb swap partition. currently, this linux system is only used by a few users for storing small files; however, the department manager wants to upgrade this system and use it to run a database application that will be used by 100 users. the database application and the associated data will take up over 200gb of hard disk space. in addition, these 100 users will store their personal files on the hard disk of the system. each user must have a maximum of 5gb of storage space. the department manager has made it very clear that this system must not exhibit any downtime as a result of hard disk errors. how much hard disk space will you require, and what partitions would you need to ensure that the system will perform as needed? where would these partitions be mounted? what quotas would you implement? what commands would you need to run and what entries to /etc/fstab would you need to create? justify your answers.

Use a software program or a graphing utility with matrix capabilities to solve the system of linear equations using an inverse matrix. x1 + 2x2 − x3 + 3x4 − x5 = 6 x1 − 3x2 + x3 + 2x4 − x5 = −6 2x1 + x2 + x3 − 3x4 + x5 = 3 x1 − x2 + 2x3 + x4 − x5 = −3 2x1 + x2 − x3 + 2x4 + x5 = 5

4. does the kernel phenotype distribution support the idea that the cob is the result of a dihybrid cross? what information supports your answer? if a dihybrid cross (i.e. f1 to f2 of standard mendelian crosses) is not indicated what conditions might contribute to this finding.