Consider a memory-management system based on paging. let the total size of the physical memory be 2gb laid out over pages of size 4kb. let the logical address space of each process be limited to 128mb. based on the information above, determine the physical address layout in the system (i. e., the total number of bits in a physical address, the number of bits specifying the physical frame number, and the number of bits specifying the page displacement). how many physical frames are there in the system? determine the logical address layout in a similar way. how many pages are there in the logical address space of each process? finally, compute the number of entries in each page table and the size of each page table entry. based on the computation above, identify the true statement from among those below. there are a total 32,768 frames in the system. each logical address has a total of 27 bits, with 15 bits for the page number and 12 bits for displacement. there are 524,288 entries in the page table of each process. there are 16 times as many logical pages in each process space as there are physical frames.