Achemist has 4.0 g of silver nitrate and needs to prepare 2.0 l of a 0.010 m solution. how many grams of solid silver nitrate will be left over after the solution is made?

Molarity of a solution is defined as the number of moles of solute dissolved in 1 L solvent.
The molarity required in the solution to be prepared - 0.010 M
the volume of the solution to be prepared  - 2.0 L
In 1 L of solution there should be 0.010 mol
Therefore in 2.0 L solution, number of moles required - 0.010 mol/L x 2.0 L
the number of silver nitrate moles required - 0.020 mol
Molar mass of silver nitrate - AgNO₃ - 169.9 g/mol
Mass of silver nitrate needed to make solution - 0.020 mol x 169.9 g/mol 
Mass required - 3.4 g
chemist had 4.0 g and 3.4 g needed to make the solution
leftover solid AgNO₃ after the reaction is 4.0 - 3.4 = 0.6 g of AgNO₃

It has to be b i hope this

The answer is c) pyrite