A6.55 g sample of aniline (c6h5nh2, molar mass = 93.13 g/mol) was combusted in a bomb calorimeter with a heat capacity of 14.25 kj/°c. if the initial temperature was 32.9°c, use the information below to determine the value of the final temperature of the calorimeter. 4 c6h5nh2(l) + 35 o2(g) → 24 co2(g) + 14 h2o(g) + 4 no2(g)

The final temperature of the calorimeter will be 48.619 .

The complete question has given the enthalpy for the reaction, = 1.28 kJ.

The complete reaction is:

The moles of the aniline combusted in the bomb calorimeter:

weight of aniline = 6.55 g

molecular weight = 93.13 g/mol

moles = 0.07 moles.

The equation utilized that, for 4 moles of aniline enthalpy is 1.28   kJ.

For 0.07 moles of aniline, =

= 224 kJ.

Given, The heat capacity = 14.25 .

Initial temperature = .

Heat capacity of reaction =

heat capacity of the reaction =

final temperature - initial temperature =

Final temperature - = .

Final temperature - = 15.71  

Final temperature = 15.71 + 32.9

Final temperature = 48.619 .

The final temperature of the calorimeter will be 48.619 .

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