Calculate how to prepare 250.00 ml of approximately 1.0 m hcl solution from the 2.5 m hcl solution. show your work.

Add 150 ml of water to 100 ml of 2.5 M stock solution.

Explanation: According to the neutralization law,

where,

= molarity of stock solution = 2.5 M

= volume of stock solution = ?

= molarity of desired solution = 1.0 M

= volume of desired solution = 250 ml

Now put all the given values in the above law, we get the volume of stock solution.

Therefore, 100 ml of 2.5 M of stock solution is taken and 150 ml of water is added to make the volume to 250 ml.

answer: the figure is attached herewith.

step-by-step explanation:   we are given to sketch a unit circle and label the terminal points corresponding to

in the attached figure, we have drawn a unit circle, with centre at o(0,0) and radius 1 unit. we have labelled the points a, b, c, d and e corresponding to the angles below

∠aox = 60°,

∠box = 120°,

∠cox = 180°,

∠dox = 240°,

∠eox = 300°.

and the coordinates are a(0.5,1), b(-0.5,1), c(-1,0), d(-0.5,-1) and e(0.5,-1).

thus, the answer is complete.