Chemistry, 29.07.2019 09:00 josephaciaful

How many milliliters of 0.200 m fecl3 are needed to react with an excess of na2s to produce 1.38 g of fe2s3 if the percent yield for the reaction is 65.0%? 3 na2s(aq) + 2 fecl3(aq) → fe2s3(s) + 6 nacl(aq)?

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Answers

100 ml

Explanation:

1) Convert 1.38 g of Fe₂S₃ into number of moles, n

i) Formula: n = mass in grass / molar mass

ii) molar mass of Fe₂S₃ =2 x 55.8 g/mol + 3 x 32.1 g/mol = 207.9 g/mol

iii) n = 1.38 g / 207.9 g/mol = 0.00664 moles of Fe₂S₃

2) Use the percent yield to calculate the theoretical amount:

65% = 0.65 = actual yield/ theoretical yield =>

theoretical yield = actual yield / 0.65 = 0.00664 moles / 0.65 = 0.010 mol Fe₂S₃

3) Chemical equation:

3 Na₂S(aq) + 2 FeCl₃(aq) → Fe₂S₃(s) + 6 NaCl(aq)

4) Stoichiometrical mole ratios:

3 mol Na₂S : 2 mol FeCl₃ : 1 mol Fe₂S₃ : 6 mol NaCl

5) Proportionality:

2moles FeCl₃ / 1 mol Fe₂S₃ = x / 0.010 mol Fe₂S₃

=> x = 0.020 mol FeCl₃

6) convert 0.020 mol to volume

i) Molarity formula: M = n / V

ii) V = n / M = 0.020 mol / 0.2 M = 0.1 liter = 100 ml

Answer from: erinxmeow8

100mL of $\rm \bold { Fe_2Cl_3}$ is needed to react with an excess of $\rm \bold {Na_2 S}$ to produce 1.38 g of $\rm \bold { Fe_2S_3}$ .

The reaction is

$\rm \bold{3 Na_2S(aq) + 2 FeCl_2(aq) \rightarrow Fe_2S_3(s) + 6 NaCl(aq)}$

The mass of $\rm \bold { Fe_2S_3}$ is 1.38 g

The number of moles of $\rm \bold { Fe_2S_3}$ will be 0.00664 moles.

If the if the percent yield for the reaction is 65.0% or 0.65.

$\rm \bold { Theoritical Yield = \frac{0.00664}{0.65} }\\\\\rm \bold { Theoritical Yield = 0.01 Moles}$

Since 2 mole of $\rm \bold { Fe_2Cl_3}$ is needed to produce 1 mole of $\rm \bold { Fe_2S_3}$ .

$\rm \bold { Fe_2Cl_3}$ concentration is 0.020 mol

To find the from molarity formula

$\rm \bold { V = \frac{n}{M} = \frac{0.020 mol}{ 0.2 M} / = 0.1 liter = 100 ml}\\\\\rm \bold { V = \frac{0.020 mol}{ 0.2 M} }\\\\\rm \bold { V = 0.1 liter = 100 ml}$

Hence we can conclude that 100mL of $\rm \bold { Fe_2Cl_3}$ is needed to react with an excess of $\rm \bold {Na_2 S}$ to produce 1.38 g of $\rm \bold { Fe_2S_3}$ .

To know more about, molarity. refer to the link:

link

Answer from: Quest

on passing the small ampere of electric current through the tube made of ar and hg of cfl generates uv rays which excites the fluorescent and thus emits the high radiation by consumption of just 5- 12 w in comparison to incandescent light which requires more power such as around 40 - 55 w to lighten.

moreover the life span of fluorescent or cfl is around 8000 h whereas the life span of incandescent is around 1200 h

hence, the building installed with incandescent lights bears more electricity bill.

Answer from: Quest

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How many milliliters of 0.200 m fecl3 are needed to react with an excess of na2s to produce 1.38 g o...