What is the maximum mass of methane (ch4) that can be burned if only 1.0 g of oxygen is available and how do you figure it out?

0.28 g of

Explanation:

You need a balanced equation first. ⇒

You need to find the number of moles of oxygen, which is mass divided by the Mr: 1 ÷ 32 = 1/32

Then you find the moles of methane using the mole ration oxygen to methane 2:1.  1/32 ÷ 2 = 1/64

Then you find the mass by multiplying the Mr with the number of moles:

1/64 × 18 = 0.28125 g  = 0.28 g

- aluminum and copper chloride.

- the chloride ion to separate the aluminum from the oxygen so that the aluminum can react with the copper ions (and the water molecules).