BRAINLIEST +20 pts Given trapezoid ABCD with vertices A(1,2) B(7,5) C(5,7) and D(3,6)

The length of the midsegment in simplest radical form is

The equation of the line containing the midsegment is

step-by-step explanation:

this is not possible to solve with the info given.   you need at least an one angle somewhere.

a

step-by-step explanation:

jjddbdhid r

the answer to question 1 is -8, 28.

step-by-step explanation:

answer:   the paragraph proof is mentioned below.

step-by-step explanation:

given: in a δxwy where

such that, ∠wzx ≅ ∠yzx and zw≅zy

we have to prove that: segment zx is a perpendicular bisector of segment wy.

prove: since, zw≅zy ⇒ ∠wzy is a supplementary angle.

then, ∠wzy= 180°

⇒∠wzx + ∠yzx = 180° ( because xz divides ∠wzy into two parts)

but, ∠wzx ≅ ∠yzx ( given)

⇒∠wzy+∠wzy=180° ( by substitution)

⇒2∠wzy=180°

⇒∠wzy=90°

⇒∠wzy=∠yzx =90°

therefore, xz⊥wy where wz=zy

⇒zx is a perpendicular bisector of wy.