If the reaction of 5.87 moles of potassium with excess hydrobromic acid produced an 84.8% yield of hydrogen gas, what was the actual yield of hydrogen gas?

Answer is:     2,488 mol.chemical reaction: 2k +2hbr  → 2kbr + h₂.n(k) = 5,87mol.%product = 84,8% = 0,848.n(h₂) = ? n - amount od substance.n(k) : n(h₂) = 2 : 1.5,87 mol : n(h₂) = 2: 1.n(h₂) = 2,935 mol, if reaction is 100%.actual moles 0,848  · 2,935 mol = 2,488 mol.

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