Which reaction below represents the electron affinity of li? which reaction below represents the electron affinity of li? li(g) + e- → li-(g) li(g) + e- → li+(g) li+(g) → li(g) + e- li(g) → li+(g) + e- li+(g) + e- → li(g)?

The electron affinity of Li can be represented as .

Explanation:

The electron affinity is the ability to gain electrons by the atom. On the addition of electrons, the atom imparts a negative charge on itself.

(a)

In this on the addition of electron, a negative charge is imparted.

(b)

The metal is present in the solid-state and for the reaction to proceed it must be in the gaseous state. SO, this can't be the answer.

(c)

Since there is no addition of the electron in the atom, the reaction can not be the electron affinity reaction.

(d)

Li is in solid-state with no extra electron. It is unable to remove the electron.

(e)

This has the lithium in the ionic state and with a lack of one electron. On gaining an electron, the Li will result in the charged state of +2. So, this is not the correct representation.

The correct representation for the reaction is an option (a).

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it forms an anion that has a larger radius. anions have a negative charge and are larger than the original atom.