Mathematics, 03.10.2019 03:00 wcraig1998

A) consider the weighted voting system (q: 8,4,2,1). find the banzhaf power distribution of this weighted voting systwm when q=12.

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Answer from: noahtheking67

(q: 8,4,2,1)

q = 12

List all coalitions ( 2 pair)

$(P_1,P_2)=\text{Total weight }=8+4=12 \\(P_1,P_3)\text{Total weight }=8+2=10 \\(P_1,P_4)\text{Total weight }=8+1=9 \\(P_2,P_3)\text{Total weight }=4+2=6 \\(P_2,P_4)\text{Total weight }=4+1=5 \\(P_3,P_4)\text{Total weight }=2+1 = 3$

Those whose total weight is equal to q or more than q will go further in the list of winning coalitions

So, $(P_1,P_2)=\text{Total weight }=8+4=12$ will go further in winning coalition

Coalitions ( 3 pair or more)

$(P_1,P_2,P_3)=\text{Total weight }=8+4+2=14 \\(P_1,P_2,P_4)\text{Total weight }=8+4+1=13 \\(P_1,P_3,P_4)\text{Total weight }=8+2+1=11 \\(P_2,P_3,P_4)\text{Total weight }=4+2+1=7 \\(P_1,P_2,P_3,P_4)\text{Total weight }=8+4+2+1=15$

Those whose total weight is equal to q or more than q will go further in the list of winning coalitions

$(P_1,P_2,P_3)=\text{Total weight }=8+4+2=14$

$(P_1,P_2,P_4)\text{Total weight }=8+4+1=13$

$(P_1,P_2,P_3,P_4)\text{Total weight }=8+4+2+1=15$

winning coalitions:

(P_1,P_2)

(P_1,P_2,P_3)

(P_1,P_2,P_4)

(P_1,P_2,P_3,P_4)

In case of (P_1,P_2)

If Player 1 leaves

So, total weight will be 4

So, Player 1 is critical

If Player 2 leaves

So, total weight will be 8

So, Player 2 is critical

In case of (P_1,P_2,P_3)

If Player 1 leaves

So, total weight will be 4+2=6

So, Player 1 is critical

If Player 2 leaves

So, total weight will be 8+2=10

So, Player 2 is critical

If Player 3 leaves

So, total weight will be 8+4=12

So, Player 3 is not critical since total weight is equal to q

In case of (P_1,P_2,P_4)

If Player 1 leaves

So, total weight will be 4+1=5

So, Player 1 is critical

If Player 2 leaves

So, total weight will be 8+1=9

So, Player 2 is critical

If Player 4 leaves

So, total weight will be 8+4=12

So, Player 4 is not critical since total weight is equal to q

(P_1,P_2,P_3,P_4)

If Player 1 leaves

So, total weight will be 4+2+1=7

So, Player 1 is critical

If Player 2 leaves

So, total weight will be 8+2+1=11

So, Player 2 is critical

If Player 3 leaves

So, total weight will be 8+4+1=13

So, Player 3 is not critical since total weight is greater than q

If Player 4 leaves

So, total weight will be 8+4+2=14

So, Player 4 is not critical since total weight is greater than q

Player Times critical Banzhaf power index

1 4 $\frac{4}{8} \times 100 = 50\%$

2 4 $\frac{4}{8} \times 100 = 50\%$

3 0 0

4 0 0

Sum = 8

Answer from: Quest

I’m not sure i’m sorry

Answer from: Quest

answer: hey there,

the answer you are looking for is a..

hope this you!

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