Acontainer holds 35.8 moles of gas under 10.0 atm of pressure at 70.0 c. what is the volume of the container?

THE ANSWER

for solving this, we just use the formula of the equation of state

PV = n RT
where
P: pressure =10atm
V volume
n number of mole = 35.8 moles
R universal gas constant = 0.082
T: The temperature= 70°C= 343.15 Kelvin

therefore, for finding V
we have 
 
V= (n RT) / P = 35.8 x 0.082 x 343.15   / 10 = 100.7 ≈ 101 L

the answer is V = 101L

60.0 - there are 3 significant numbers

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