A compound has an empirical formula of C3H10 and a molar mass of 92.26 g/mol. What is its molecular formula?

C6H20

Explanation:

Use this formula to convert emperical to molecular:

Actual mm (molar mass) = n(emperical mm)

Emperical mm:

C3H10= 3(12.01)+10(1.01)=46.04g/mol

Now plug in:

92.26=n(46.04)

n=2.00391

Round it as 2

Then take the n value and multiply it with the subscripts of the emperical formula:

(C3H10)2

C6H20

a:

by the combination of an unlimited number of elements

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