1. Why is it difficult for primary alcohols to form alkenes when treated with potassium hydroxide and ethanol, while secondary and tertiary alcohols do. 2. Why is it difficult for primary alcohols to undergo reaction with acidified water.​

oxidation of alcohols involves the alkyl portion of the molecule, or more specifically, the \(\ce{C-H}\) bonds of the hydroxyl-bearing carbon (the \(\alpha\) carbon). Secondary alcohols, which have only one such \(\ce{C-H}\) bond, are oxidized to ketones, whereas tertiary alcohols, which have no \(\ce{C-H}\) bonds to the hydroxylic carbon, are oxidized only with accompanying degradation into smaller fragments by cleavage of carbon-carbon bonds.Because alcohols are easily synthesized and easily transformed into other compounds, they serve as important intermediates in organic synthesis.Explanation:

Not sure but hope it helps

The problem here is that according to aufbau principle before 3d orbital 4s subshell comes.after filling 3p orbital with electrons you have 4 electrons left, you place two in 4s with opposite spin and the other two in 3d in any of its two orbitals of total five orbitals with the same spin.