Answers: 3
Chemistry, 21.06.2019 23:30
Problem #3 (ch. 1, problem 15)the ideal gas law provides one way to estimate the pressure exerted by a gas on a container. the law isÑťÃ‘ť=ћÑ›Ã‘›Ã‘›Ã‘›Ã‘›Ã‘‰Ã‘‰more accurate estimates can be made with the van der waals equationÑťÃ‘ť=ћÑ›Ã‘›Ã‘›Ã‘›Ã‘›Ã‘‰Ã‘‰â’ћÑ›Ã‘źÃ‘źâ’ўÑžÃ‘›Ã‘›2щщ2where the term nb is a correction for the volume of the molecules and the term an2/v2is a correction for molecular attractions. the values of a and b depend on the type of gas. the gas constant is r, the absolutetemperature is t, the gas volume is v, and the number of moles of gas molecules is indicated by n. if n = 1 mol of an ideal gas were confined to a volume of v = 22.41 l at a temperature of 0â°c (273.2k), it would exert a pressure of 1 atm. in these units, r = 0.0826.for chlorine gas (cl2), a = 6.49 and b = 0.0562. compare the pressure estimates given by the ideal gas law and the van der waals equation for 1 mol of cl2 in 22.41 l at 273.2 k. what is the main cause of the difference in the two pressure estimates, the molecular volume or the molecular attractions?
Answers: 1
Chemistry, 22.06.2019 08:30
In the millikan oil drop experiment they determined that every drop had a charge which was a while number multiple of -1.60x10^-19. if a drop has a total charge of -9.60x10^-19 then how many excess electrons are contained within the drop?
Answers: 2
Chemistry, 22.06.2019 10:00
The reactions shown here can be combined to make the overall reaction c(s) + h2o(g) ⇌ co(g) + h2(g) by reversing some and/or dividing all the coefficients by a number. a. c(s) + o2(g) → co2(g) k=1.363×10^69 b. 2 h2(g) + o2(g) → 2 h2o(g) k=1.389×10^80 c. 2co(g) + o2 (g) → 2 co2(g) k=1.477×10^90
Answers: 1
Ii. Given the following substances CCl4 (1), HCl(g), KCL(g), CuCl 2(3) State which of them
a. Has...
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