11. What is the balanced equation for this reaction, which takes place in a basic solution? Cr(OH)3( s) + ClO3 –( aq) → CrO4 2( aq) + Cl –( aq) Cr(OH)3( s) + 2ClO3 –( aq) + 4OH –( aq) → 2CrO4 2 –( aq) + Cl –( aq) + 3H2O( l) 2Cr(OH)3( s) + ClO3 –( aq) + 4OH –( aq) → 2CrO4 2 –( aq) + Cl –( aq) + 5H2O( l) Cr(OH)3( s) + 2ClO3 –( aq) + 6OH –( aq) → 3CrO4 2 –( aq) + 2Cl –( aq) + 2H2O( l) 2Cr(OH)3( s) + 2ClO3 –( aq) + 6OH –( aq) → 2CrO4 2 –( aq) + 2Cl –( aq) + 7H2O( l)

because of all the things that happen around the us, many people get into arguments which sadly could get physical, but we should actually make a change for that.

each chemical family is represented as a group or column on the periodic table. based on chemical properties, there are 6 types of chemical families. group 1 represents alkali metals, group 2 represents alkaline earth metals, groups 3 to 12 represent transition metals, groups 13 to 16 represent non-metals and other metals, group 17 represents halogens and group 18 represents noble gases.

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.

substituting a hydrogen atom with a halogen in a hydrocarbon:

- the single bond remains single. a is wrong.

- the bond with hydrogen is as strong as with a halogen. c is wrong

- a hydrocarbon is saturated if there is no double bond. we do not know that so d is wrong.

- carbon will always have four valence electrons. e is wrong.

by elimination, the correct answer is b. the boiling point of the new compound increases.