What is the oxidation state of N in NaNO3?

What is the Oxidation Number of N in NaNO3. The oxidation of nitrogen is +5. The NaNO 3 molecule is neutral. This means that the negative charges must be equal to the positive charges within the NaNO 3 molecule. In the Arrhenius acid-base sense, sodium nitrate, NaNO 3, is not acidic or basic.

Explanation:

What is the Oxidation Number of N in NaNO3. The oxidation of nitrogen is +5. The NaNO 3 molecule is neutral. This means that the negative charges must be equal to the positive charges within the NaNO 3 molecule. In the Arrhenius acid-base sense, sodium nitrate, NaNO 3, is not acidic or basic.

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%