Calculate the volume of oxygen produced at STP from 172 grams of potassium chlorate, KClO3, in the following reaction: KClO3 → KCl + O2 Show your work.

64.2 L

Explanation:

In order to be able to calculate the volume of oxygen gas produced by this reaction, you need to know the conditions for pressure and temperature.

Since no mention of those conditions was made, I'll assume that the reaction takes place at STP, Standard Temperature and Pressure.

STP conditions are defined as a pressure of

100 kPa

and a temperature of

0

∘

C

. Under these conditions for pressure and temperature, one mole of any ideal gas occupies

22.7 L

- this is known as the molar volume of a gas at STP.

So, in order to find the volume of oxygen gas at STP, you need to know how many moles of oxygen are produced by this reaction.

the electron configuration that you gave me has 16 electrons ergo it has 16 protons ergo it is the element sulfur.

you didnt put any of the following