At 300.0 K and 0.987 atm pressure, what will be the volume of 2.30 mol of Ne?

V = 57.39 L

Explanation:

Given that,

Temperature, T = 300 K

Pressure, P = 0.987 atm

No. of moles of Ne, n = 2.30 mol

We need to find the volume of Ne. We know that, the ideal gas law is as follows :

PV = nRT

Where

P is pressure and R is gas constant

So, the volume of the Ne is 57.39 L.

it would be d. henry moseley

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