PH =5 and now to prepare a buffer solution what will be the proportion of ethanoic acid and sodium ethanoate

CH3COONa : CH3COOH =  1.74 :  1  (required to prepare a buffer at PH = 5)

Explanation:

Given that :

PH = 5

Calculate proportions of ethanoic acid and Sodium ethanoate to prepare Buffer solution

solution :  

PH = Pka + Log ( CH3COONa / CH3COOH )

5.0 = 4.76 +  Log ( CH3COONa / CH3COOH )

∴  Log ( CH3COONa / CH3COOH ) = 0.24

( CH3COONa / CH3COOH )  = 1.74

Therefore : CH3COONa : CH3COOH

                         1.74          :      1

it would be d. henry moseley

hope this !

and sorry if i'm late. have a good rest of your day! : d