3.523 x 10^24 molecules of Mg(OH2) will need how many grams of H3PO4 in the reaction below H=1.01 g/mol
P=30.97 g/mol
O=16.00 g/mol

3 Mg(OH)2 + 2 H3PO4 -> 1 Mg3 (PO4 )2 + 6 H2O

c. 75.7

i think that is the right

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

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