Pd(NO₃)₂ + NaCl ---> PdCl₂ + NaNO₃ 140 grams of lead (II) nitrate (Pd(NO₃)₂) are dissolved in water then mixed with a solution containing 75 grams of sodium chloride (NaCl). The reaction creates the precipitate, lead (II) Chloride (PdCl₂), and a solution of sodium nitrate (NaNO₃) . How many grams of lead (II) Chloride can be produced given the initial amount of lead (II) nitrate?

Stoichometry based.

All I need is the set up, but you can give answer if you want.

Please help.

Answer the questions about this reaction: nai(aq) + cl2(g) → nacl(aq) + i2(g) write the oxidation and reduction half-reactions: oxidation half-reaction: reduction half-reaction: based on the table of relative strengths of oxidizing and reducing agents (b-18), would these reactants form these products? write the balanced equation: answer options: a. 0/na -> +1/na+1e- b. nai(aq) + cl2(g) → nacl(aq) + i2(g) c. +1/na+1e- -> 0 /na d. -1/2i -> 0/i2+2e- e. no f. 4nai(aq) + cl2(g) → 4nacl(aq) + i2(g) g. 2nai(aq) + cl2(g) → 2nacl(aq) + i2(g) h. 4nai(aq) + 2cl2(g) → 4nacl(aq) + 2i2(g) i. nai(aq) + cl2(g) → nacl(aq) + i2(g) j. 0/cl2+2e -> -1/2cl- k. yes

What is the indicator of the number of ions in solution? the amount of conductivity the amount of precipitate the amount of solute added

Ok, so i have 2 questions. try to answer them both: (the topic is fire) 1) how can you represent the chemical reaction of fire? 2) what kind of bond is formed in this chemical reaction