Calculate the molarity of a solution of NH4Cl that contains 53.5 g of the salt dissolved in 100.0 g of water at 80 °C. The density of the solution is 1.12 g/mL

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Answer:             1.0  × 10⁻⁵ msolution:                     as we know ph is given as,                                    ph  = -log [h⁺]and,                                    [h⁺]  =  10^-ph    (1)putting value of ph in eq. 1,                                    [h⁺]  =  10⁻⁵                                    [h⁺]  =  1.0  × 10⁻⁵ m