The volume of a gas is 0.668 L at 66.8°C. At what Celsius temperature will the gas have a volume of 0.942 L, assuming the pressure remains constant.

206 c

Explanation:

Use the Charles' Law because you have the volume and temperature given.

V1 / T1 = V2 / T2

Let's list the given:

V1 = 0.668 L

V2 = 0.942 L

T1 = 66.8 C (339.8K)

Convert all Celsius temps to Kelvin. Just add 273.

Asked: T2

Derive the formula for T2.

T2 = V2T1 / V1

    = (0.942)(339.8) / 0.668

    = 479K

Since the temp should be in C, just subtract 273 from 479K.

The answer is 206 C.

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.

the correct answer to this question is 2