What is the molarity of a solution of cu2so4 if 250.0 ml of solution contains 14.1 g of cu2so4?

A is 14.1 g

B is 0.0632 mol

C is 250.0 mL

D is 0.253 M

Explanation:

I divided 14.1 g (A) by 223.2 and got 0.0632 mol (B).

For the second part, I divided 0.0632 by 250.0 mL (C) since 1000 is mL.

Then I used the equation and got 0.253 M (D)

the answer is:  

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