Balanced chemical equation for the use of hydrogen fuel

I'm not sure but I think is 2H2 => 4H+ + 4e- and O2 + 4H+ + 4e- => 2H2O

Answer:             1.0  × 10⁻⁵ msolution:                     as we know ph is given as,                                    ph  = -log [h⁺]and,                                    [h⁺]  =  10^-ph    (1)putting value of ph in eq. 1,                                    [h⁺]  =  10⁻⁵                                    [h⁺]  =  1.0  × 10⁻⁵ m