In an experiment, 0.35 mol of co and 0.40 mol of h2o were placed in a 1.00-l reaction vessel. at equilibrium, there were 0.22 mol of co remaining. keq at the temperature of the experiment is

The equilibrium constant of reaction at given temperature is 0.28.

Explanation:

Initially  

0.35 mol        0.40 mol  

At equilibrium

(0.35 mol-x)       (0.40 mol-x)       x           x

Moles of CO left at equilibrium = 0.22 mol

0.22 mol = (0.35 mol-x)

x = 0.35 mol - 0.22 mol = 0.13 mol

Moles of left at equilibrium = 0.40 mol - 0.13 mol = 0.27 mol

Concentration of CO at equilibrium =

Concentration of at equilibrium =

Concentration of at equilibrium =

Concentration of at equilibrium =

The equilibrium constant of reaction at given temperature is 0.28.

answer: -

reaction:

na + cl ⇌ nacl

balanced chemical equation:

na + 2cl ⇌ nacl2

sodium + clorine goes to form sodium chloride (table salt).

the product is nacl2.

and the reactants are na and cl.

(note: if you don’t know what ⇌ means, read below: -

⇌(double head arrow) means reversible reaction).

the answers would be

the first one and the second one