Complete these structures by adding electron dots as needed.

This is hard to show but here is how you would determine these. NOTE each dot is an electron. 
Question 1) 
F-H 
1) determine the valance electrons for each. F has 7 and H has 1 
2) one electron from both F and H form the bond "-" which means that you still have 6 electrons to place around F and none to place around H. Place the 6 in sets of 2 around the F 
.. 
F-H 
¨ 
Question 2) 

2) H-O-H 
H has 1 valence electron minus 1 used in the bond to O = 0 electrons to place 
H has 1 valence electron minus 1 used in the bond to O = 0 electrons to place 
O has 6 valence electrons minus 2 used in the bonds to the H's = 4 electrons to place 

H-O-H: place two dots above and below the oxygen 

Question 3) 
3) O=NH : NOTE: a double bond requires O and N to share two of their electrons each 
O has 6 valence electrons minus 2 used in the bonds to N = 4 electrons to place 
N has 5 valence electrons minus 3 used in the bonds to O and H = 2 electrons to place 
H has 1 valence electron minus 1 used in the bond to N = 0 electrons to place 
place the 2 dots on top and bottom of oxygen. 
place 2 above the N 

Answer : option c) heat is released during the process.explanation :

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.