What is the hybridization of the central atom of each of the following molecules? a.) h2o b.) pbr5 c.) cocl2? you so much!

 The notion of hybrid orbitals was "invented" by Linus Pauling in 1931 to explain the observed geometry of mostly organic molecules. Today, we find that hybrid orbitals are pretty much confined to the central atoms found in the second period of the periodic table. Periods 3 and up not so much. 

(a) H2O O is the central atom, tetrahedral, sp3 hybridization 
(b) PBr5 P is the central atom, maybe sp2 for the three equatorial bonds * 
(c) COCl2.. C is the central atom, trigonal planar, sp2 hybridization 

100%sorry if i’m wronghope this good luck: )

For cyclohexane compounds drawn in a chair conformation:   -axial bonds are vertical  -equatorial bonds are parallel to two bonds within the ring.  thus, as i assume the chair conformation is drawn:   -the x group is in an axial position, as are the five other vertical bonds.  -three axial bonds are on the top face of the ring  -the other three axial bonds are on the bottom face  the position of the second substituent on each ring carbon is equatorial.  gauche groups must be on an adjacent carbon such as carbon 6 and carbon 2, and also gauche groups are rotated by 60 degrees relative to each other.  drawing the newman projections for c1–c2 and c1–c6 aids in visualizing the groups that are gauche to the y group on c1.  click this link and watch some academic videos that may you more understand the topic