If 10.00 moles of copper are reacted with 6.00 moles of sulfur according to the following balanced equation, which reactant is the limiter and how many moles of excess reactant would remain after the reaction is completed? 2 Cu + S --> Cu2S Cu is limiting and 1.00 mole of excess S remain

S is limiting and 1.00 moles of excess Cu remain

S is limiting and 4.00 moles of excess Cu remain

Cu is limiting and 4.00 moles of excess S remain

Cu is limiting and 1.00 mole of excess S remain

Explanation:

The chemical balanced reaction is:

According to stoichiometry :

2 moles of require 1 mole of

Thus 10.00 moles of will require=  of

Thus is the limiting reagent as it limits the formation of product and is the excess reagent.

Moles of S left = (6.00-5.00) moles = 1.00 mole

Thus Cu is limiting and 1.00 mole of excess S remain.

the answer is 0.8m.

by: nicholas

atomic mass = 39

number of neutrons = 20

number of protons= 19

electronic configuration = 1s2 2s2 2p6 3s2 3p6 4s1

the number of electron in first shell = 2

number of electrons in n=3 shell = 8