A saturated solution is prepared by adding excess PbI2 (s) to distilled water to form 1.0L of solution at

25°C. The concentration of Pb
2+
(aq) in the same saturated solution is found to be 1.3 x 10
-3 M. The

chemical equation for the dissolution of PbI2

(s) in water is shown below.

PbI2
(s) ⇄ Pb
2+
(aq) + 2 I
-
(aq)

a. Write the equilibrium-constant expression for the equation
b. Calculate the molar concentration of I
-
(aq) in the solution
c. Calculate the value of the equilibrium constant, Ksp
d. An additional 1.0 L of water is added, bringing the total volume of the solution to 2.0 L and the
solution remains saturated. Calculate the molar concentration of Pb
2+
(aq) in the solution.

e. Solid NaI is added to the saturated solution of PbI2

. Assuming the volume of the solution does

not change, does the molar concentration of Pb
2+
(aq) in the solution increase, decrease, or

remain the same? Justify your answer.

nacl or sodium chloride is an ionic compound. this is because an ionic compound pertains to a compound that consists of positively and negatively charged ions. in this case, na (sodium) has a tendency to lose one electron when it reacts with with other atoms, so the resulting sodium ion contains 11 protons and 10 electrons, thus making it positively charged (na+), when chlorine reacts, it usually gains one electron to form an ion called chloride, thus making it negatively charged ( since the ions are oppositely charged, they attract.

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.