What will the volume of 2.5 moles of gas be at 281K and 102 kPa?

V = 57.23

Explanation:

Using the ideal gas law (PV = nRT), we plug in the variables for moles, Kelvin, and pressure: (102 * V = 2.5 * R * 281). We plug in the correct R constant value for the type of pressure we are using (atm, Kpa, or mmHg) with values of (0.0821, 8.31, or 62.4) respectively. Since we are using kPa in this example, we use 8.31 for the R constant so we get: (102 * V = 2.5 * 8.31 * 281). We solve the right side to get: (102 * V = 5837.775). We divide 102 sides from both sides to get that (V = 57.233)

answer: i dont know the answer but this might

explanation:

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it can be observed without changing the identity of the object.

it depends on what substance you're talking about as well as many other factors. in quantum mechanics, the observation of particles affects the observers ability to measure certain properties. for example: you can know the velocity of a particle, but you can't know it's position; or you can know it's position, but not it's velocity. it's like trying to find out where a grain of sand is by throwing other grains of sand at it. once you find out where it is, it's been moved. it's also like trying to find an answer to the question of whether or not a tree falling in a forest makes a sound if nobody is there to hear it. paradoxically, the only way to find out is to be there and hear it.