Water with a flowrate of 1 m3/min and benzene concentration of 150 mg/L flows through a 10 meter long, 0.1 m diameter steady state and conservative PFR, after which it is fed into a CMFR with a volume of 100 m3. A second water stream with a flowrate of 0.5 m3/min and benzene concentration of 150 mg/L is also fed into the CMFR. The CMFR is steady state and conservative. Calculate the effluent concentration of the CMFR.

the effluent concentration of the CMFR is 150 mg/L

Explanation:

Given that;

flowrate of first water Q₁ = 1 m³/min

benzene concentration C₁ = 150 mg/L

flowrate of second water Q₂ = 0.5 m3/min

benzene concentration C₂ =  150 mg/L

To Calculate the effluent concentration of the CMFR, we use the expression;

= (Q₁C₁ + Q₂C₂) / Q₁ + Q₂

we substitute

= (1 × 150 + 0.5 × 150) / 1 + 0.5

= 225 / 1.5

= 150 mg/L

Therefore, the effluent concentration of the CMFR is 150 mg/L

answer; i believe that the correct answer is (a) potassium(k)

the potential energy of the reactants is 200j.

from the energy diagram, the energy of the product formed is 350j; this means that, this reaction is an endothermic reaction, because it absorbs energy from its environment.