Tin reacts with fluorine to form two different compounds, a and b. compound a contains 38.5 g of tin for each 12.3 g of fluorine. compound b contains 56.5 g of tin for each 36.2 g of fluorine. what is the lowest whole-number mass ratio of tin that combines with a given mass of fluorine?

In compound A, the mass ratio of Tin to Fluorine is 1 : 2

In compound B, the mass ratio of Tin to Fluorine is 1 : 4

Explanation: For the reaction of Tin and Fluorine, the reaction follows:

To calculate the mass ratio, we simply find the mole ratio and for that we need to find the moles of Tin and fluorine respectively for each compound and then divide it by the lowest number of moles.

Molar mass Tin = 118.71g/mol

Molar mass Fluorine = 19g/mol

Formula to calculate the moles is:

For Compound A:

Moles of Tin =

Moles of Fluorine =

Mole ratio of Tin is =

Mole ratio of Fluorine =

Mass ratio of Tin and fluorine is 1 : 2. The compound formed is

For Compound B:

Moles of Tin =

Moles of Fluorine =

Mole ratio of Tin is =

Mole ratio of Fluorine =

Mass ratio of Tin and fluorine is 1 : 24 The compound formed is

considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.