How much heat energy is required to boil 87.7 g of ammonia, nh3? the molar heat of vaporization of ammonia is 23.4 kj/mol.

Energy released from changing the phase of a substance from the gas phase to liquid phase can be calculated by using the specific latent heat of vaporization. Calculation are as follows:

 Energy = 87.7 g (1 mol / 17.04 g) x 23.4 kJ/mol

Energy = 120.4 kJ

the correct answer is answer a. a mixture

no other options make sense

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