How many molecules of SO₃ can be formed from 0.35 moles of O₂ (assuming excess SO₂) from the following UNBALANCED equation? SO₂(g) + O₂(g) → SO₃(g)

The number of molecules of SO₃ that could be formed is 4.2 × 10²³ molecules

From the question,

We are to determine the number of molecules of SO₃ that could be formed.

The given chemical equation for the reaction is

SO₂(g) + O₂(g) → SO₃(g)

First, we will balance the chemical equation

The balanced chemical equation for the reaction is

2SO₂(g) + O₂(g) → 2SO₃(g)

This means

2 moles of SO₂ reacts with 1 mole of O₂ to produce 2 moles of SO₃

From the given information

Number of moles of O₂ present = 0.35 moles

Since,

2 moles of SO₂ reacts with 1 mole of O₂ to produce 2 moles of SO₃

Then,

2×0.35 mole of SO₂ will react with the 0.35 mole of O₂ to produce 2×0.35 mole of SO₃

That is,

0.70 mole of SO₂ will react with the 0.35 mole of O₂ to produce 0.70 mole of SO₃

∴ 0.70 mole of SO₃ could be produced

Now, for the number of molecules of SO₃ that could be produced,

Using the formula

Number of molecules = Number of moles × Avogadro's constant

∴ Number of molecules of SO₃ that could be formed = 0.70 × 6.022 × 10²³

Number of molecules of SO₃ that could be formed = 4.2154 × 10²³  

Number of molecules of SO₃ that could be formed ≅ 4.2 × 10²³ molecules

Hence, the number of molecules of SO₃ that could be formed is 4.2 × 10²³ molecules

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Molecules of SO₃  : 4.214 x 10²³

The reaction equation is the chemical formula of reagents and product substances  

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products  

Reaction(balanced)

2SO₂(g) + O₂(g) → 2SO₃(g)

mol SO₃ :

number of molecules :

1 mol = 6.02 x 10²³ particles(atoms, molecules,ions)

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