A mixture of 40 mol % isopropanol in water is distilled at 1 atm by differential distillation until 70 mol % of the charge has been vaporized (equilibrium data are given in Exercise 7.33). What is the composition of the liquid residue in the still pot and of the collected distillate

Explanation:

From the given information:

The percentage wieght of mixture = 0.4

The distillate = 70

From equilibrium data in Exercise 7.33

The Feed W = 100

The Liquid residue F = Feed(W) - Distillate (D)

= 100 - 70 = 30

By applying rayleigh equation;

From the plot of the graph of ; the area under the curve is being calculated between the point { }.

Such that; the area = 1.209

Similarly, the value of xF = 0.067

∴

answer is: c. the experiment shows that the red substance experienced a chemical change.

this is chemical change (chemical reaction), because two new substances are formed (metalig liquid and gas), the atoms are rearranged and the reaction is followed by an energy change.

this is example of chemical decomposition.

chemical decomposition (analysis) is the separation of a single chemical compound into its two or more elemental parts or to simpler compounds.  

chemical decomposition is opposite of chemical synthesis.