Explain why only a substitution product and no elimination product is obtained when the following compound reacts with sodium methoxide: A line-angle formula shows a ring with six vertices. A CH3 group is attached to the first and the third (clockwise) vertices with a wedge. A Br atom is attached to the second vertex with a dash.

Hydrogen and the Bromine substituents must be in the axial position for elimination reaction to occur.

If the Bromine is in axial position it means that the beta carbon containing the hydrogen will NOT be in axial position. Thus, no elimination reaction will occur.

Explanation:

The chemical compound known as Sodium methoxide is a whitish substance with chemical formula of CH3NaO, Melting point of 127 °C, Molar mass of 54.03 g/mol and Boiling point of 350 °C. It is a very important chemical substance that is used in the manufacturing of other useful substances.

From the description of the compound that will be reacted with sodium methoxide in the question, one should not expect elimination reaction to occur IF THE ELIMINATING SUBSTITUENTS ARE NOT IN THE AXIAL POSITION(that is to say the Hydrogen and the Bromine substituents must be in the axial position for elimination reaction to occur.

Thus, If the Bromine is in axial position it means that the beta carbon containing the hydrogen will NOT be in axial position. Thus, no elimination reaction will occur.

a:

by the combination of an unlimited number of elements

elements make up everything, and they combine to make compounds.

the answer is c