MY NOTES ASK YOUR TEACHER Consider a different titrant for this exercise. Suppose Ca(OH)2 were used as the titrant, instead of NaOH. This will make the titrant twice as concentrated in hydroxide ion. The analyte will still be HC2H3O2. (a) What is the stoichiometry of HC2H3O2 to Ca(OH)2

The stoichiometry of the reaction is 1:2.

Stoichiometry shows mass - mole relationship. Mass - mole relationships are very important in chemical arithmetic. All calculations in stoichiometry are based on the balanced chemical reaction equation.

The reaction equation for the reaction between Ca(OH)2 and HC2H3O2 is shown as follows; Ca(OH)2(aq) + 2HC2H3O2(aq) > Ca(C2H3O2)2(aq) + 2H2O(l). The stoichiometry of the reaction is 1:2.

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The stoichiometry of HC₂H₃O₂ to Ca(OH)₂ is 1 : 2

To obtain the stoichiometry of HC₂H₃O₂ to Ca(OH)₂, we shall write the equation for the reaction. This is given below:

The above equation can be balanced as follow:

There are 2 atoms of C on the left side and 4 atoms on the right side. It can be balanced by writing 2 before HC₂H₃O₂ as shown below:

2HC₂H₃O₂ + Ca(OH)₂ —> Ca(C₂H₃O₂)₂ + H₂O

There are a total of 10 atoms of H on the left side and a total of 8 atoms on the right side. It can be balanced by writing 2 before H₂O as shown below:

2HC₂H₃O₂ + Ca(OH)₂ —> Ca(C₂H₃O₂)₂ + 2H₂O

Now, the equation is balanced.

From the balanced equation above, the mole ratio of HC₂H₃O₂ to Ca(OH)₂ is 1 : 2

Therefore, the stoichiometry of HC₂H₃O₂ to Ca(OH)₂ is 1 : 2

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explanation:

metals have excess of electrons whereas non-metals have deficiency of electrons. thus, in order to gain stability metals easily donate their electrons to the non-metals.

for example, electronic configuration of sodium is and electronic configuration of phosphorous is .

when a phosphorous atom and sodium atom combine together then sodium will donate is extra one electron to the phosphorous atom. as a result there will be formation of ionic bond between sodium and phosphorous.

the reaction will be as follows.

there, are three sodium sodium atoms and each of them will donate its one extra electron to phosphorous atom. thus, the sub-shell of phosphorous gets completely filled.  

thus, we can conclude that electrons are transferred from atoms of sodium to atoms of phosphorous. this transfer makes the sodium atoms donate one electron and the phosphorous atoms to gain one electron. as a result, the sodium and phosphorus atoms strongly attract each other.

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