How many grams of K2Cr207 are in 250. mL of 0.500M of K2Cr207: 36.8 g
73.6 g
294 g
18.2 g

Analysing the Question:

We are given a 250 mL solution of 0.5M K₂Cr₂O₇

Which means that we have:

0.5 Mole in 1L of the solution

0.125 moles in 250 mL of the solution      [dividing both the numbers by 4]

Mass of K₂Cr₂O₇ in the given solution:

Molar mass of K₂Cr₂O₇(Potassium Dichromate) = 194 g/mol

we know that we have 0.125 moles in the 250 mL solution provided

Mass = Number of moles * Molar mass

Mass = 0.125 * 194

Mass = 36.75 grams

sorry idk the answer well to you i have a explaination

explanation: a formula which shows the arrangement of atoms in the molecule of a compound

explanation:

metals have excess of electrons whereas non-metals have deficiency of electrons. thus, in order to gain stability metals easily donate their electrons to the non-metals.

for example, electronic configuration of sodium is and electronic configuration of phosphorous is .

when a phosphorous atom and sodium atom combine together then sodium will donate is extra one electron to the phosphorous atom. as a result there will be formation of ionic bond between sodium and phosphorous.

the reaction will be as follows.

there, are three sodium sodium atoms and each of them will donate its one extra electron to phosphorous atom. thus, the sub-shell of phosphorous gets completely filled.  

thus, we can conclude that electrons are transferred from atoms of sodium to atoms of phosphorous. this transfer makes the sodium atoms donate one electron and the phosphorous atoms to gain one electron. as a result, the sodium and phosphorus atoms strongly attract each other.