g Determine the percent enantiomeric excess of a sample with specific rotation of 14 compared to an enantiomerically pure reference stereoisomer of the sample that has specific rotation -24

Explanation:

Enantiomeric excess of this compound X is given by the formula

EE= Observed specific rotation*100 / maximum specific rotation

EE= 14*100/24 = 58.33%

Percentage enantiomeric excess

%(-) = EE/2 +50

       = 58.33/2 + 50

        = 79.12% OF (-)X and 20.88% of (+) X

the child will have heterozygous dominant chromosomes as characters of his father are dominant over the characters of his mother.

the child is heterozygous

hloride, what is the mass of calcium in

explanation: