0 molmol of H2H2 is allowed to react with 0.500 molmol of I2I2 in a 1.00 LL reaction vessel at 700 KK, what is the concentration of I2I2 at eq

Explanation:

Hello.

In this case, when hydrogen and iodine react at equilibrium, the reaction is:

So the equilibrium expression is:

Which can be also written in terms of the ICE chart knowing that Kc is 57.0:

Whereas the initial concentrations of both hydrogen and iodine are 0.100 M (0.500mol/1.00L), thus, we write:

Which can be solved as follows:

Therefore, the concentration of iodine at equilibrium is:

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