15.05 ml of a KOH solution neutralizes 25.6 mL of a 5.0 M H2SO4 solution. What is the concentration of the KOH solution?

The concentration of KOH solution is 17.009 moles/litre or 17.009M .

Explanation:

Here , the given reaction is -

 2moles of KOH requires 1mole for complete neutralisation.

Therefore ,

2 x number of moles of KOH = 1 x number of moles of

2 x (molarity of KOH x volume of KOH) = (Molarity of x volume of

)

1 mole of 1mole of

Molarity (KOH) = concentration (c)

volume (KOH) =15.05ML

Molarity ( ) = 5.0 M

Volume of ( ) = 25.6ML

C =

C= 17.009 moles/litre

Hence , the concentration of KOH solution is 17.009 M or moles/litre .

under a microscope, cancer cells may look very different from normal cells. they often have different sizes and some may be larger than normal while others are smaller. cancer cells are often abnormally shaped and the control centre of the cell (the nucleus) may have an abnormal appearance.

i think? ?

answer : one can design an experiment using a liquid and an additive that can be added to the liquid and observe the chemical changes in the reaction species.

one would need a beaker which is filled with a known amount of the liquid in which thermometer is placed to measure the temperature changes; after addition of the additive to the liquid solution one can note down the temperature change and find whether the reaction is endothermic or exothermic in nature. by subtracting the initial temperature value with the final temperature one can find the temperature changes.

various combinations of liquid and additive can be used. liquid in this case can be a known quantity of water and additives can be epsom salt or without epsom salt the experiment can be conducted to notice the changes. water and ice, hydrogen peroxide and dry yeast, vinegar and baking soda,etc.