What is the mass, in grams, of 8.65 x 1025 atoms of oxygen?

Mass = 2304 g

Explanation:

Given data;

Number of atoms of oxygen = 8.65×10²⁵

Mass in gram = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.  The number 6.022 × 10²³ is called Avogadro number.

For example,

1 mole = 6.022 × 10²³ atoms

8.65×10²⁵ atoms of oxygen× 1mol  /6.022 × 10²³ atoms

1.44×10² mol

144 mol

Mass in grams of oxygen:

Mass = number of moles × molar mass

Mass = 144 mol × 16 g/mol

Mass = 2304 g

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

your answer is c) plasma

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