Directions:In the questions6, 7 and 8given below, there are two statements labelled as Assertion (A)and Reason (R).Mark your answer as per the codes provided below:(i). Both A and R are true and R is the correct explanation of A.(ii). Both A and R are true but R is not the correct explanation of A.(iii). A is true but R is false.(iv). A is false but R is true.6.Assertion (A): A saturated solution becomes super saturated on cooling. Reason (R): Solubility decreases with decrease in temperature.7. Assertion (A): Silver bromide is a compound which is made of the elements silver and bromine. Reason (R): Silver bromide is a pure substance.8.Assertion (A): Acetone and water are immiscible liquids. Reason (R):A mixture of acetone and water can be separated by simple distillation.

Use the gizmo to find the concentration of the mystery ch3cooh. use the titrant and indicator shown below perform the titration. what is the titrant volume? titrant analyte indicator titrant volume analyte concentration naoh ch3cooh phenophthalein select one: a. 20.0 ml b. 27.0 ml c. 30.0 ml d. 24.0 ml

Microtubular fibers that assist in the movement of chromosomes during nuclear division in conjunction with proteins, makes up the small and large organelle pieces that assemble prior to translation three-base nucleotide sequence that can complementarily pair with the functional transcript, allowing a particular material to be brought to a ribosome particular time in the cell cycle when the cell’s systems determine if the cellular conditions are appropriate to continue through the cycle time in the cell’s cycle when proteins are made and organelles are duplicated enzyme that allows proper nucleotide bonding during transcription specific dna sequence which will initiate gene transcription division of the cell’s cytoplasm specific bond that forms between two amino acids when a carboxyl group binds to a amino group three-base sequence that does not code for a particular amino acid a paired organelle which facilitates the formation of movement microtubules time in the cell’s cycle when the microtubular structures exert an equal pressure on the cell’s genetic material

Two nitro no2 groups are chemically bonded to a patch of surface. they can't move to another location on the surface, but they can rotate (see sketch at right). it turns out that the amount of rotational kinetic energy each no2 group can have is required to be a multiple of ε, where =ε×1.010−24 j. in other words, each no2 group could have ε of rotational kinetic energy, or 2ε, or 3ε, and so forth — but it cannot have just any old amount of rotational kinetic energy. suppose the total rotational kinetic energy in this system is initially known to be 32ε. then, some heat is removed from the system, and the total rotational kinetic energy falls to 18ε. calculate the change in entropy. round your answer to 3 significant digits, and be sure it has the correct unit symbol.