How much energy is required when a 142.1 gram sample of aluminum goes from 25.5°C to 46°C? (the specific heat of aluminum is 0.90 J/g °C).

2621.75 j heat is required to increase the temperature 25.5°C to 46°C.

Explanation:

Given data:

Mass of sample = 142.1 g

Initial temperature = 25.5°C

Final temperature = 46°C

Specific heat capacity of Al = 0.90 J/g.°C

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 46°C - 25.5°C

ΔT = 20.5°C

Q = 142.1 × 0.90 J/g.°C × 20.5°C

Q = 2621.75 j

Thus,  2621.75 j heat is required to increase the temperature 25.5°C to 46°C.