A rock falls from a cliff and travels downward for 6 seconds before striking the ground. How fast was the rock moving when it hits the ground? Assume there is no air resistance.

Given parameters:

duration of fall  = 6s

Unknown:

Speed of the rock before it hits the ground  = ?

Solution:

To solve this problem, we apply one of the appropriate motion equations;

           V = u + gt

Where V is the final velocity

           u is the initial velocity

           t is the time taken

           g is the acceleration due to gravity  = 9.8m/s²

The initial velocity is 0;

     So;

              V = gt

Input the parameters and solve for V;

                V = 9.8 x 6  = 58.8m/s

The velocity before hitting the ground is 58.8m/s

samuel de champlain. in 1608, king henry iv sponsored pierre dugua, sieur de mons and samuel de champlain as founders of the city of quebec with 28 men. this was the second permanent french settlement in the colony of canada.