Consider the combustion of butane: 2C4H10(g)+ 1302(g)= 8CO2(g) +10H2O(1) if
you have 50.0 grams
butane, how many moles
of butane do you have?
use the following atomic
weights C = 17.0 g/mole; H
1.0g/mole; O= 16. Og/mole

you need to take a look at the periodic system in order to sort these elements into pairs that would most likely exhibit similar chemical properties. first, you need to find elements that are found in the same group (groups are vertical in the periodic system), and then to see whether they have the same valence number. if they meet these criteria, they will have similar properties.

the first pair: ne (neon) and kr (krypton), are noble gases found in group 8

the second pair: li (lithium) and k (potassium), found in group 1

the third pair: s (sulfur) and te (tellurium), found in group 6

the answer is   c.) 1575 j.

explanation:

a gas, having a molecular weight of 13 kg/kmol and a kinematic viscosity of 0.25 cm2/s, flows through a pipe 0.25 m internal diameter and 5 km long at the rate of 0.4 m3/s and is delivered at atmospheric pressure.