What is the net ionic equation of 2K (s) + Cd(NO3)2 (aq) --> 2K(NO3) + Cd ?

2K^+(aq) + 2NO3^-(aq) —> 2K(NO3)

Explanation:

2K (s) + Cd(NO3)2 (aq) —> 2K(NO3) + Cd

We can obtain the net ionic equation for the above reaction as follow:

Cd(NO3)2 will dissociate in solution as follow:

Cd(NO3)2 (aq) –> Cd^2+(aq) + 2NO3^-(aq)

K(s) –> K^+(aq)

Therefore:

2K (s) + Cd(NO3)2 (aq) —> 2K(NO3) + Cd

=>

2K^+(aq) + Cd^2+(aq) + 2NO3^-(aq) —>

2K(NO3) + Cd^2+(aq)

We shall cancel out Cd^2+ from both side of the equation to obtain the net ionic equation as shown below:

2K^+(aq) + 2NO3^-(aq) —> 2K(NO3)

Therefore, the net ionic equation for the reaction is

2K^+(aq) + 2NO3^-(aq) —> 2K(NO3)

the grams   of   barium that   are in   2.3 x 10^23   atoms of barium   is   52.4 g (answer c)

    calculation

mass = moles   of ba   x molar   mass of ba

  molar mass of ba from periodic table=   137.3 g/mol

  use the   avogadro's law   constant   to   calculate the moles of barium

  that   is     1 mole =   6.02   x 10^23 atoms

                    ? moles = 2.3 x 10^23   atoms

by cross   multiplication

=(1 mole   x 2.3x 10^23 atoms)   / 6.02   x10^23 atoms)=   0.382   moles

mass   is therefore = 137.3   g/mol x 0.382 mol = 52.4 ( answer c)

explanation:

oxygen, selenium, tellurium, and polonium.

they're all from the same group as sulfur (group 16).