A balloon is inflated with 0.2494g of helium to a pressure of 1.26atm. If the desired volume of the balloon is 1.250L, what must the temperature be in ⁰C?

307.80K

Explanation:

Mass = 0.2494g

Pressure = 1.26atm

Volume = 1.25L

Temperature (T) = ?

Molar mass of He = 4.0g/mol

To solve this question, we'll have to use ideal gas equation which is

PV = nRT

P = pressure of the gas

V = volume which the gas occupies

n = number of moles of the gas

R = ideal gas constant = 0.082J/mol.K

T = temperature of the ideal gas

n = number of moles = mass / molarmass

n = 0.2495 / 4.0

n = 0.0624moles

PV = nRT

T = PV / nR

T = (1.26 × 1.25) / (0.0624 × 0.082)

T = 1.575 / 0.0051168

T = 307.80K

The temperature of the gas is 307.80K

in the analysis of systems that involve fluid flow, we frequently encounter the combination of properties u and pv.

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